Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The centre of a circle passing through the points (0, 0), (1, 0) & touching the circle x 2 + y 2 = 9 is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b,d)Equation of circle passing through (0, 0) and (1, 0) is
x 2 + y 2 – x + 2fy = 0 .......(i)
x 2 + y 2 = 9 ......(ii)
(i) & (ii) touch each other.
so equation of Radical axis is x = 2fy + 9 ......(iii)
line (iii) is also tangent to the circle (ii)
∴ on solving (ii) & (iii), we get
(1 + 4f 2 )y 2 + 36fy + 72 = 0 .......(iv)
∴ D = 0 ⇒ f = ± 
.
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